## INDEX

### CHECKING LEAP YEAR USING C PROGRAM

Definition of leap year:

Rule 1: A year is called leap year if it is divisible by 400.
For example: 1600, 2000 etc leap year while 1500, 1700 are not leap year.
Rule 2: If year is not divisible by 400 as well as 100 but it is divisible by 4 then that year are also leap year.
For example:  2004, 2008, 1012 are leap year.

Leap year logic or Algorithm of leap year or Condition for leap year:

IF year MODULER 400 IS 0
THEN leap_year
ELSE IF year MODULER 100 IS 0
THEN not_leap_year
ELSE IF year MODULER 4 IS 0
THEN leap_year
ELSE
not_leap_year

Code 1:
1. C program to determine leap year
2. C program to find leap year or not
3. Leap year calculation in c

#include<stdio.h>
int main(){
int year;

printf("Enter any year: ");
scanf("%d",&year);

if(((year%4==0)&&(year%100!=0))||(year%400==0))
printf("%d is a leap year",year);
else
printf("%d is not a leap year",year);

return 0;
}

Sample output:
Enter any year: 2010
2010 is not a leap year

Code 2:
1. Write a program to find leap year in c
2. How to find leap year in c code

#include<stdio.h>
int main(){
int year;
int min_year,max_year;

printf("Enter the lowest year: ");
scanf("%d",&min_year);

printf("Enter the heighest year: ");
scanf("%d",&max_year);

printf("Leap years in given range are: ");
for(year = min_year;year <= max_year; year++){
if(((year%4==0)&&(year%100!=0))||(year%400==0))
printf("%d ",year);
}

return 0;
}

Sample output:
Enter the lowest year: 2000
Enter the highest year: 2011
Leap years in given range is: 2000 2004 2008

10. Write a c program to add two numbers without using addition operator.
11. Write a c program to subtract two numbers without using subtraction operator.
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28. Write a c program which takes password from user.
29. Write a scanf function in c which accept sentence from user.
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1. thanks a lot

2. please make a change of if statement

if(((year%4==0)&&(year%100!=0))||(year%400==0))

3. Great work :) thanks a lot.. my doubt got cleared ...

4. thanks a lot

5. explain?

6. great job yarrrr

7. YOU CAN TRUNCATE THE MIDDLE PART NUM%100 BECAUSE THERE ARE SOME LEAP WHOSE MODULUS ARE EQUAL TO HUNDERED

8. why dont u write it as year%4==0
it means year divided by 4 leaves remainder 0..
is it correct?

9. can u help me do it without using if statement

10. write a c program swapping of to no with out using third variable & with out using addition & substracting?

11. thanks a lot ritesh

12. 1500 and 1700 are leap years...
you mentioned that it is not a leap year...

1. From wiki: 1600 was a leap year, but 1700, 1800 and 1900 were not.
To understand concept of leap year I hope this link will help you: Concept of leap year

13. i hav a doubt...anybody can clear tis pls??? is thr any need to divide a year by 100?? y r v using tat???

1. I hope this will helpful ..

1600, 2000 etc leap year while 1500, 1700 are not leap year.

// if we enter 1500

if ( ( (year%4==0) && (year%100!=0)) || (year%400==0) )
{
// according to this 1500 not a leap year..
}
-----------------------------------
if ( (year%4==0) || (year%400==0) )
{
// according to this 1500 a leap year..
}

14. very useful

15. thanx bud!

16. can you do same program without using any logical operator?

17. int main(){

int year;

printf("Enter any year: ");

scanf("%d",&year);

if(((year%4==0)&&(year%100!=0))||(year%400==0))

printf("%d is a leap year",year);

else

printf("%d is not a leap year",year);

return 0;

}

..............................................................
I think it's a wrong code.
when I try 2200 it shows that the year isn't leap year.
...............................................................
I think the code will be,

int main(){

int year;

printf("Enter any year: ");

scanf("%d",&year);

if(year%4==0)

printf("%d is a leap year",year);

else

printf("%d is not a leap year",year);

return 0;

}
..........................................................................
If I'm wrong , please explain......

1. Wrong because year%4==0 is not the necessary condition for any year to be a leap year.

2. Wrong because year%4==0 is not the necessary condition for any year to be a leap year.

18. my code is correct or incorrect???plz help me.
if any mistake plz tell me???
Write a program that a year you enterd is leap year or not
#include
void main()
{
int year;
printf("Enter the Year = ");
scanf("%d",&year);
if(year%4==0)
printf("Leap Year ");
else
printf("Not Leap Year");
}

1. #include
int main()
{
int year;
scanf("%d",&year);
if(year%4==0)
{
if(year%100==0)
{
if(year%400==0)
{
printf("%d This is leap year:",year);
}
else
{
printf("%d this is not a leap year:",year);
}

}
else
{
printf(" %dThis is not leap year:",year);
}
}
else
{
printf(" %d This is not leap year:");
}

return 0;
}

19. my code is correct or incorrect???plz help me.
if any mistake plz tell me???
Write a program that a year you enterd is leap year or not
#include
void main()
{
int year;
printf("Enter the Year = ");
scanf("%d",&year);
if(year%4==0)
printf("Leap Year ");
else
printf("Not Leap Year");
}

20. good for practicing this sight guys

21. "C program to check leap year"
Question:
How do i tweak the output of this code:
~let say i type in 2012 and the output should be February 29, 2014 Wednesday is a leap year (same thing with the other leap year)
~ i type in 2013 and the output should be 2013 is not a leap year.

22. what if we need to enter day-month-year as input
how we want to determine the day of the year?
for sample output
Enter date:25-12-2014
This is day 359 0f year 2014

23. Thanks for these code, Here I have explained the math to solve the programm. Like why we will not take the year divisible by 100.

24. Thanks a lot........!!!

25. can anyone explain why we are using %100 n %400 ?

26. can anyone help? sometimes it went to wrong. when a year is possible to divisible by 400 along with 100 that time what would i do? like 2000, 1200, 1600,

#include
int review()//Function for review the calculation...
{
int year;
int i=400;
int d=100;
int m=4;
if(year%i==0){
printf("Your entered Year is divisble by %d",i);
}
else if(year%d==0)
{
printf("Your entered Year is divisble by : %d",d);
}
else if(year%m==0)
{
printf("Your entered year is divisble by%d",m);
}
else{
printf("May be there is a error in input:");
printf("Try again!");
}
return 1;
}

int main()
{
//check the year if it is leap year
int year;
while(year!=0){
printf("\nEnter a Year:\n");
scanf("%d",&year);

//}
if(year%400==0)//(if a year divisble by 400 then it is leap year.)
{
printf("This is leap year:%d",year);
}
else if(year%100==0)//(If a year is divisble by 100 then it is not a leap year)
{
printf("This year is not leap year:%d",year);
}
else if(year%4==0)//(If a year divisble by 4 then it is leap year....)
{
printf("This is leap year:%d",year);
}
else{
printf("This is not leap year. ");
}
printf("\nReview");
printf("\n________________________________________________\n");
review();

}
return 0;
}

27. I
I think this code is the exact solution for finding leap year::::::::::::: can you try this ????

else
{
printf(" %dThis is leap year:");
}

Here some condition............

28. #include
int main()
{
int year;
scanf("%d",&year);
if(year%4==0)
{
if(year%100==0)
{
if(year%400==0)
{
printf("%d This is leap year:",year);
}
else
{
printf("%d this is not a leap year:",year);
}

}
else
{
printf(" %dThis is not leap year:",year);
}
}
else
{
printf(" %d This is not leap year:");
}

return 0;
}