Pointer to function in c programming

Function pointer definition:  A pointer which keeps address of a function is known as function pointer.  

Examples of function pointers in c:


(1) What will be output if you will execute following code?

#include<stdio.h>
int * function();
int main(){
auto int *x;
int *(*ptr)();

ptr=&function;
x=(*ptr)();
printf("%d",*x);

return 0;
}
int *function(){
static int a=10;
return &a;
}

Output: 10
Explanation: Here function is function whose parameter is void data type and return type is pointer to int data type.
x=(*ptr)()
=> x=(*&functyion)() //ptr=&function
=> x=function() //From rule *&p=p
=> x=&a
So, *x = *&a = a =10


(2) What will be output if you will execute following code?

#include<stdio.h>
int find(char);
int(*function())(char);
int main(){

int x;
int(*ptr)(char);

ptr=function();
x=(*ptr)('A');
printf("%d",x);

return 0;
}
int find(char c){
return c;
}
int(*function())(char){
return find;
}

Output: 65
Explanation: Here function whose name is function which passing void data type and returning another function whose parameter is char data type and return type is int data type.

x=(*ptr)(‘A’)
=> x= (*function ()) (‘A’) //ptr=function ()
//&find=function () i.e. return type of function ()
=> x= (* &find) (‘A’)
=> x= find (‘A’) //From rule*&p=p
=> x= 65

(3) What will be output if you will execute following code?

#include<stdio.h>
char * call(int *,float *);
int main(){

char *string;
int a=2;
float b=2.0l;
char *(*ptr)(int*,float *);

ptr=&call;
string=(*ptr)(&a,&b);
printf("%s",string);

return 0;
}

char *call(int *i,float *j){
static char *str="c-pointer.blogspot.com";

str=str+*i+(int)(*j);
return str;
}

Output: inter.blogspot.com
Explanation: Here call is function whose return type is pointer to character and one parameter is pointer to int data type and second parameter is pointer to float data type and ptr is pointer to such function.
str= str+*i+ (int) (*j)
=”c-pointer.blogspot.com” + *&a+ (int) (*&b)
//i=&a, j=&b
=”c-pointer.blogspot.com” + a+ (int) (b)
=”c-pointer.blogspot.com” +2 + (int) (2.0)
=”c-pointer.blogspot.com” +4
=”inter.blogspot.com”

(4) What will be output if you will execute following code?

#include<stdio.h>
char far * display(char far*);
int main(){

char far* string="cquestionbank.blogspot.com";
char far *(*ptr)(char far *);

ptr=&display;
string=(*ptr)(string);
printf("%s",string);

return 0;
}
char far *display(char far * str){

char far * temp=str;

temp=temp+13;
*temp='\0';

return str;
}

Output: cquestionbak
Explanation: Here display is function whose parameter is pointer to character and return type is also pointer to character and ptr is its pointer.
temp is char pointer
temp=temp+13
temp=’\0’
Above two lines replaces first dot character by null character of string of variable string i.e.
"cquestionbank\0blogspot.com"
As we know %s print the character of stream up to null character.

Definition of pointer
How to read complex pointer
Arithmetic operation with pointer
Pointer to function
Pointer to array of function
Pointer to array of string
Pointer to structure
pointer to union
Multi level pointer
Pointer to array of pointer to string
Pointer to three dimentional array
Pointer to two dimensional array
C tutorial

3 comments:

Harish said...

but prototype of call function is already defined.

Ashok said...

You rock man...

deep said...

please tell me how "c-pointerblogspot.com"+4 becomes interblogspot.com?