Write a c program to find out L.C.M. of two numbers.





LCM program in c with two numbers : 

#include<stdio.h>
int main(){
  int n1,n2,x,y;
  printf("\nEnter two numbers:");
  scanf("%d %d",&n1,&n2);
  x=n1,y=n2;
  while(n1!=n2){
      if(n1>n2)
           n1=n1-n2;
      else
      n2=n2-n1;
  }
  printf("L.C.M=%d",x*y/n1);
  return 0;
}

LCM program in c with two numbers (Other logic) :



#include<stdio.h>

int lcm(int,int);

int main(){

   

    int a,b,l;

    printf("Enter any two positive integers ");
    scanf("%d%d",&a,&b);
 
    if(a>b)
         l = lcm(a,b);
    else
         l = lcm(b,a);
   
    printf("LCM of two integers is %d",l);

    return 0;
}

int lcm(int a,int b){
  
    int temp = a;

    while(1){
         if(temp % b == 0 && temp % a == 0)
             break;
         temp++;
    }

   return temp;
}

LCM program in c with multiple numbers :




#include<stdio.h>

int lcm(int,int);



int main(){

   
    int a,b=1;
    printf("Enter positive integers. To quit press zero.");

    while(1){
         scanf("%d",&a);
         if(a<1)
             break;
         else if(a>b)
             b = lcm(a,b);
         else
             b = lcm(b,a);
    }

    printf("LCM is %d",b);

    return 0;
}

int lcm(int a,int b){
 
    int temp = a;

    while(1){
         if(temp % b == 0 && temp % a == 0)
             break;
         temp++;
    }

    return temp;
}





Definition of LCM (Least common multiple):

LCM of two integers is a smallest positive integer which is multiple of both integers that it is divisible by the both of the numbers.
For example: LCM of two integers 2 and 5 is 10 since 10 is the smallest positive numbers which is divisible by both 2 and 5.




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