Write a c program to print Pascal triangle







#include<stdio.h>

int main(){
  int length,i,j,k;

 //Accepting length from user
  printf("Enter the length of pascal's triangle : ");
  scanf("%d",&length);

 //Printing the pascal's triangle
  for(i=1;i<=length;i++) {
            for(j=1;j<=length-i;j++)
                        printf(" ");
            for(k=1;k<i;k++)
                        printf("%d",k);
            for(k=i;k>=1;k--)
                        printf("%d",k);
            printf("\n");
  }

  return 0;
}





5 comments:

heera said...

thi program shud give the pascals triangle for a limited number


#include

int fact(int n)
{ int ctr,pro=1;
for(ctr=n;ctr>0;ctr--)
pro*=ctr;
return pro;
}

int combi(int n, int r)
{ int c;
c=fact(n)/(fact(r)*fact(n-r));
return c;
}

main( )
{ int n,ctr1,ctr2,r,num,cm;
printf(“Enter the number of rows to be displayed :”);
scanf(“%d”,&n);
num=num;
for(ctr1=0;ctr1<n;ctr++,num--)
{ for(r=0;r<=ctr1;r++)
{cm=combi(ctr1,r);
if(r= =0)
{ for(ctr2=0;ctr2<(2*num)-1;ctr2++)
printf(“ “);
printf(“%d”,cm);
}

else
{ for(ctr2=0;ctr2<3;ctr2++)
printf(“ ”);
printf(“%d”,cm);
}
}
printf(“\n”);
}
}

sanjay samant said...

great job

bijay kc said...

try this one


#include
#include
main()
{
int length,i,j,k;
//Accepting length from user
printf("Enter the length of pascal's triangle : ");
scanf("%d",&length);

//Printing the pascal's triangle
for(i=1;i<=length;i++) {
for(j=1;j<=length-i;j++)
printf(" ");
for(k=1;k=1;k--)
printf("%d",k);
printf("\n");
}

getch();
}

v.ajay Kumar said...

#include
#include
#include
void main()
{
int i,j,k,n,p;
printf("enter no of rows:");
scanf("%d",&n);
fflush(stdin);
for(i=1;i<=n;i++)
{
for(j=1;j<=n-i-1;j++)
printf(" ");
for(k=1;k<=2*i-1;k++)
p=pow(11,i-1);
printf(" %d\t",p);
printf("\n");
}
getch();
}

Anonymous said...

yes it will surely give pascal triangle upto a certain limit but this is much longer than the program for pascal triangle(mentioned above)