**Write a c program or code to find out the sum of series 1^3 + 2^3 + …. + n^3 that is sum of cube of n natural numbers.**

#include<stdio.h>

#include<math.h>

int main(){

int n,i;

int sum=0;

printf("Enter
the n i.e. max values of series: ");

scanf("%d",&n);

sum = pow(((n * (n +
1) ) / 2),2);

printf("Sum of
the series : ");

for(i
=1;i<=n;i++){

if (i != n)

printf("%d^3 + ",i);

else

printf("%d^3 = %d ",i,sum);

}

return 0;

}

Sample
output:

Enter the n i.e. max values
of series: 3

Sum of the series: 1^3 + 2^3
+ 3^3 = 36

**Mathematical Formula:**

Sum of the series 1

^{3}+ 2^{3 }+ 3^{3}+ … + n^{3}= (n (n+1)/2)^{2}
6.
Write a c program to find out the sum of given H.P.

If
you have any suggestions on above

**sum of cube of n natural numbers**, please share us.