**C program for generic root**

#include<stdio.h>

int main(){

long int num,sum,r;

printf("\nEnter
a number:-");

scanf("%ld",&num);

while(num>10){

sum=0;

while(num){

r=num%10;

num=num/10;

sum+=r;

}

if(sum>10)

num=sum;

else

break;

}

printf("\nSum of
the digits in single digit is: %ld",sum);

return 0;

}

**C code for calculation of generic root in one line**

#include <stdio.h>

int main(){

int num,x;

printf("Enter any number: ");

scanf("%d",&num);

printf("Generic root: %d",(x=num%9)?x:9);

return 0;

}

**Sample output:**

Enter any number: 731

Generic root: 2

**Meaning of generic root**:

It sum of digits of a number unit
we don't get a single digit. For example:

Generic root of 456: 4 + 5 + 6 = 15
since 15 is two digit numbers so 1 + 5 = 6

So, generic root of 456 = 6

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## 8 comments:

wap to find out car number with the help of following clues

1.it is 4digit number.

2.it is perfect square.

3.first two digits are same.

4.last two digits are same

7744

║#include

║#include

║#include

║void main()

║{

int a,b,c;

clrscr();

for(b=1;b<10;b++)

{

for(c=1;c<10;c++)

{

a=b+b*10+c*100+c*1000;

if(a==(int)sqrt(a)*(int)sqrt(a))

printf("%d ",a,sqrt(a));

}

}

}

there is an easier way to solve this...

This program prints the sum if it is 10

but 10 should be as 1+0=1 for the single digit sum

int sumofdigits(int num)

{

int sum=0;

int r;

while(num>9)

{

sum=0;

while(num)

{

r=num%10;

num/=10;

sum+=r;

}

if(sum>9)

num=sum;

}

return sum;

}

void main()

{

int num;

printf("Enter the number:");

scanf("%d",&num);

printf("%d",sumofdigits(num));

}

One logic may be like this:

(num-1)%9 +1;

#include

int main()

{

int r,num=90,sum=0;

if(num>=10)

{

while(num!=0)

{

r=num%10;

num=num/10;

sum+=r;

}

printf("sum=%d",sum);

}

else

printf("sum=%d",num);

return 0;

}

Cant u give me logic for counting float integer data type

if i want to take 10^10000 as input ,how can i write the code ??? please help me .

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