## INDEX

### Write a c program to find out the sum of series 1^2 + 2^2 + …. + n^2.

Sum of 1^2 + 2^2 + …. + n^2 series in c programming language

#include<stdio.h>

int main(){

int n,i;
int sum=0;

printf("Enter the n i.e. max values of series: ");
scanf("%d",&n);

sum = (n * (n + 1) * (2 * n + 1 )) / 6;

printf("Sum of the series : ");

for(i =1;i<=n;i++){
if (i != n)
printf("%d^2 + ",i);
else
printf("%d^2 = %d ",i,sum);
}

return 0;
}

Sample output:

Enter the n i.e. max values of series: 5
Sum of the series: 1^2 + 2^2 + 3^2 + 4^2 + 5^2 = 55

Mathematical Formula:

Sum of the series 12 + 22 + 32 + … + n2 =
n (n+1) (2n+1)/6

6. Write a c program to find out the sum of given H.P.

preeree said...

thanks...............

Anonymous said...

Help me
Write a C or Java program to find out the sum of series:
1! + 2! + 3! + . . . + N, with N input from keyboard

Unknown said...

thank you :)

Anonymous said...

1/x+1/x^2+1/x^3+.....

Unknown said...

Very good..

vibon said...

Dear sir, Can you have me to write total sum of 2^2+10^2+20^2+50^2+100^2 in java??

Unknown said...

1^2+3^2+5^2....................nth find out sum use for loop in c

Unknown said...

plz........ any one help me.........

Monir Hossain said...

#include
int main()
{
int n,sum=0,i;
scanf("%d",&n);
for(i=0;i<=n;i++)
{
sum=(sum+i*i);
}
printf("%d",sum);
return 0;
}

Unknown said...

please solutionthis program in C++ to generate the series as 1, 3, 4, 8, 15, 27, 50, ........

Unknown said...

please solution this program in C++ to generate the series as 1, 3, 4, 8, 15, 27, 50, ........

Unknown said...

#include
int main()
{
int n,sum=0,i;
scanf("%d",&n);
for(i=1;i<=n;i=i+2)
{
sum=(sum+i*i);
}
printf("%d",sum);
return 0;
}

Unknown said...

1^2+2^4+3^6+4^8+.............+n^2n for loop c programming code please ans me

Abhra Mitra,1997 said...
This comment has been removed by the author.
Abhra Mitra,1997 said...

your program didn't work. I did a little modification and now it works..

#include
int main()
{
int n,sum=1,i, j=0;
scanf("%d",&n);
for(i=1;i<=n; i++)
{
sum=(sum+(j*j));
j=j+2;
}
printf("%d",sum);
return 0;
}

Unknown said...
This comment has been removed by the author.
Unknown said...

1^2+2^2+n^2 /n^2 en c++ como quedaría me dijeron que fuera dando los pasos

Unknown said...

que libreria metiste para que funcionara el programa

Hasinur R Khan said...

2^2+4^4+......n^n

Unknown said...

can u help me to write a program in c to print the series
2, 6, 11, 10, 15, 21, 18, 24, 31, 26, 33, 41 .....answer me as much as possibel

Unknown said...

Write flowchart and program to read value for x and print the series 3*x^2, 5*x^2, 7*x^2.... 25th terms

Unknown said...

plz write the c code

2,6,15,28,55,78

1*2=2
2*3=6
3*5=15
4*7=28
5*11=55
6*13=78.

DigitalTechInfo said...

Plx sir
How can i solve the pyramid through this coding plx i want help its my assignment...
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