1. Write a c program to convert decimal number to hexadecimal number.
3. Write a c program to convert octal number to decimal number.
4. Write a c program to convert octal number to hexadecimal number.
5. Write a c program to convert hexadecimal number to decimal number.
6. Write a c program to convert hexadecimal number to octal number.
8. Write a c program to convert binary number to hexadecimal number.
9. Write a c program to convert binary number to octal number.
11. Write a c program to convert hexadecimal number to binary number.
12. Write a c program to convert octal number to binary number.
2 comments:
Can any1 please explain above program????
when you create pointer to structure lets say
struct student *ptr;
it will assign some memory address to its members such that
address of-
&ptr->roll 36857 the starting address
&ptr->name 36859 ( 36857 the starting address of roll + 2 bytes = 36859 the starting address of char name[100];)
&ptr->marks 36959 ( 36859 the starting address of name + 100 bytes = 36959 the starting address of float marks;)
so the address range for all members are 36857-36962 (coz the address range of marks is 36959 -36962 which is of 4 bytes).
ok now if you use statement as following like in above example
struct student *ptr=0;
it will assign starting address to 0 (zero) instead of 36857 such that
address of-
&ptr->roll 0
&ptr->name 2
&ptr->marks 102
so the address range of all members of structure will be now from 0 to 105 ( because marks will be stored at address 102-105 which is 4 bytes)
so ptr++ will increment to the starting address 106 of next structure variable which is equal the total size of structure.
hope this helps ...
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