## INDEX

### C program to print Armstrong numbers from 1 to 500

C program to print Armstrong numbers from 1 to 500

#include<stdio.h>
int main(){
int num,r,sum,temp;

for(num=1;num<=500;num++){
temp=num;
sum = 0;

while(temp!=0){
r=temp%10;
temp=temp/10;
sum=sum+(r*r*r);
}
if(sum==num)
printf("%d ",num);
}

return 0;
}

Output:
1 153 370 371 407

Algorithm:

Definition according to c programming point of view:
Armstrong numbers are those unique integers for which the sum of the cubes of their individual digits equals the original number itself.
For example 153 since 1^3 + 5^3 + 3^3 = 1+ 125 + 9 =153
Other Armstrong numbers: 370,371,407 etc.
In general definition:
Armstrong numbers are defined as integers for which the sum of each digit raised to the power of the total number of digits in the number equals the original number itself.
Example 1: 153
Total digits in 153 is 3
And 1^3 + 5^3 + 3^3 = 1 + 125 + 27 = 153
Example 2: 1634
Total digits in 1634 is 4
And 1^4 + 6^4 + 3^4 +4^4 = 1 + 1296 + 81 + 64 =1634

Examples of Armstrong numbers: 1, 2, 3, 4, 5, 6, 7, 8, 9, 153, 370, 371, 407, 1634, 8208, 9474, 54748, 92727, 93084, 548834, 1741725

Anonymous said...

what is wrong in following code??
#include
#include
main()
{
int i;
for(i=1;i<=500;i++)
{
if(i==(((i%10)^3)+(((i/10)%10)^3)+((((i/10) /10)%10)^3)))
printf("%d \n",i);
else continue;
}

}

Devavrat Mathur said...

The only flaw that I see is that c does not have ^ operator.

Unknown said...

@Anonymous first of all I looked up on your code and I tried to fix some issues, the result is almost good, but it's show just one number, 407.

Here is your code a litle bit updated:
main()
{
int i;
for(i=1;i<=500;i++)
{
if(i==(((i%10)*(i%10)*(i%10))+((((i/10)%10)*(i/10)%10)*(i/10)%10)+((((i/10) /10)%10)*(((i/10) /10)%10)*(((i/10) /10)%10))))
printf("%d \n", i);
else continue;
}

}

bandaru nikas said...

here output is 1,407;

#include

int main()
{
int n,a,b,c,d,e,f,g,h;
for (h=001;h<=500;h++){
n=h;

a=n%10;
b=n%100;
c=(b-a)/10;
d=(n-b)/100;
e=a+c+d;

if (n==(a*a*a)+(c*c*c)+(d*d*d))
{
printf("%d\n",n);
continue;
}

}
}

output is:
1
153
370
371
407

Unknown said...

Thanku sir

Unknown said...

What wrong following code
Main()
{
int i;
For(i=1;i<=500;i++)
{if==(((i%10)^3)+(((i=10)%10)^3)+((((>/10)/10)%10)^3))))
Printf("%d\n",i);
else
}
}

Life journey said...

Is it working

Anonymous said...

#include
#include
int main()

{
int a,b,c,n,i;
for(i=1;i<=500;i=i+1)
{

a=(i%10);
b=((i-a)/10)%10;
c=((i-10*b-a)/100)%10;
n=pow(a,3)+pow(b,3)+pow(c,3);
if(n==i)
printf("\n %d ",i);
else
continue;

}

}