## INDEX

### Write a c program to add two numbers without using addition operator

Add two numbers in c without using operator

How to add two numbers without using the plus operator in c

#include<stdio.h>

int main(){

int a,b;
int sum;

printf("Enter any two integers: ");
scanf("%d%d",&a,&b);

//sum = a - (-b);
sum = a - ~b -1;

printf("Sum of two integers: %d",sum);

return 0;
}

Sample output:

Enter any two integers: 5 10

Sum of two integers: 15

Algorithm:

In c ~ is 1's complement operator. This is equivalent to:
~a = -b + 1
So, a - ~b -1
= a-(-b + 1) + 1
= a + b – 1 + 1
= a + b

#### 31 comments:

Unknown said...

sir (~) tiled use karne se two number add kyun hue...kya aap xplain kr sakte h...

Unknown said...

@mohit
a+b=a-(-b)
but we know -b=(~b+1)
so
a+b=a - (~b+1)
a+b= a - ~b - 1

Anonymous said...

I m just getting crazy in making c problems and i have completed all my assignments and problems that i had in handouts or pdf's and now i got this site as a helping tool to improve my skill to professional level..... Thankx man.. for giving us problems.... :) mean c problems.... ;)

Unknown said...

here is a simple logic...adding a and b..say a=5 b=4 so a+b=5+4=9

int main(void)
{
int a=5,b=4;// you can input those nos from user...
while(b)
{
a++;
b--;
}
printf("%d",a);
}

Anonymous said...

still not clear with '~'...

Anonymous said...

~b = -(b+1)
so a-(~b)-1 = a-(-(b+1))-1
= a+b+1-1
= a+b

Unknown said...

'~' is a type of bitwise operator.
This simply means one's complement.
Bitwise operators can only be operated upon ints & chars.
On taking the one's complement of a number, all the 1's are changed to 0's and vice-versa.
e.g: one's complement of 5 (0101) is -6 (1010).

Unknown said...

This code doesn't use any arithmetic operators to add two numbers.

main()
{
int num1, num2;
scanf("%d %d",num1, num2);
printf("%d", Add(num1, num2));
}

int Add(int x, int y)
{
if (y == 0)
return x;
else
return Add( x ^ y, (x & y) << 1);
}

Unknown said...

please write explanation also. . .

Mukilan said...

while (num2) // do until carry
{
int carry = num1 & num2 // if its 1 & 1 we get carry
num1 = num1 ^ num2; // add all 0 +1 = 1
num2 = carry << 1; // now we need to carry
}
return num1

Mukilan said...

while (num2) // do until carry
{
int carry = num1 & num2 // if its 1 & 1 we get carry
num1 = num1 ^ num2; // add all 0 +1 = 1
num2 = carry << 1; // now we need to carry
}
return num1

Mukilan said...

while (num2) // do until carry
{
int carry = num1 & num2 // if its 1 & 1 we get carry
num1 = num1 ^ num2; // add all 0 +1 = 1
num2 = carry << 1; // now we need to carry
}
return num1

Anonymous said...

BH JUYHC

Anonymous said...

i cant understand

Anonymous said...

plz also share the problem for multiplication with out using * operator!!!

Unknown said...

Here is a slight modification that adds subtraction feature as well:

/* Adds two signed integers. Does a subtract when cin = 1 */
int adder(int a, int b, int cin)
{
if (cin) b = ~b;
int carry = (a & b) << 1 | cin;
a ^= b;
b = carry;

while (b) {
carry = (a & b) << 1;
a ^= b;
b = carry;
}

return a;
}

Anonymous said...

you can as well use ^ operator.
a^b will give you its sum.

Unknown said...

Good thing boss

Unknown said...

nice one

Unknown said...

void main()
{
int a=10,b=10,c;
clrscr();
c=a- -b;
printf("%d",c);
}

Unknown said...

You have used "+" operator (A++ which is A = A + 1) which is forbidden in the question itself.

Unknown said...

The mission of NCITSolutions is to provide viable, low cost outsourcing solutions. We offer you offshore services tailor made to suit your distinctive requirements. Our low cost IT solutions afford you a competitive edge while delivering tangible results. With a software team whose core competencies range from software design to graphic design, we are equipped to process all your IT needs as we operate on a vast gamut of systems such as: Linux, UNIX, Windows, iOS and Android.

NCITSolutions is an independent and unique organization that was created with the objective of facilitating offshore/outsourcing services to enable clients to benefit from potential business opportunities made available through the creation of free and fair markets in the Middle East region.

We offer:
• Individual outsourcing facilities uniquely tailored for each customer.
• Identification of available market resources and potential partners
• On-the-ground management and support in Jordan
• Legal, technical and cultural support for ventures.
Numerous global companies have set up offices in Amman- Jordan in a bid to promote partnerships and joint ventures with Middle East companies. NCITSolutions maintains a physical presence with staff on the ground in Amman- Jordan. We can also provide businesses with space and easy access to our business support services through our affiliate in Amman Jordan.

Visit us at ncitsolutions.com or contact us at 919-324-6505

Unknown said...

The mission of NCITSolutions is to provide viable, low cost outsourcing solutions. We offer you offshore services tailor made to suit your distinctive requirements. Our low cost IT solutions afford you a competitive edge while delivering tangible results. With a software team whose core competencies range from software design to graphic design, we are equipped to process all your IT needs as we operate on a vast gamut of systems such as: Linux, UNIX, Windows, iOS and Android.

NCITSolutions is an independent and unique organization that was created with the objective of facilitating offshore/outsourcing services to enable clients to benefit from potential business opportunities made available through the creation of free and fair markets in the Middle East region.

We offer:
• Individual outsourcing facilities uniquely tailored for each customer.
• Identification of available market resources and potential partners
• On-the-ground management and support in Jordan
• Legal, technical and cultural support for ventures.
Numerous global companies have set up offices in Amman- Jordan in a bid to promote partnerships and joint ventures with Middle East companies. NCITSolutions maintains a physical presence with staff on the ground in Amman- Jordan. We can also provide businesses with space and easy access to our business support services through our affiliate in Amman Jordan.

Visit us at ncitsolutions.com or contact us at 919-324-6505

Unknown said...

Simply we can do it as:
#include

int main(){

int a,b;

printf("Enter any two integers: ");
scanf("%d%d",&a,&b);

for(int i=0;i<b;i++)
{
a++;
}

printf("Sum of two integers: %d",a);

return 0;
}

Unknown said...

+ is different and ++ is different... question says without using addition operator.. ++ is not addition operator. so the solution is correct. :)

Krishna said...

~b = -(b + 1 )
This is the right ones complement .

lokesh said...

This blog is very helpful for us...I got some important information from this blog..
DOT NET Training in Chennai
DOT NET Training in Bangalore
asp .net training in chennai
dot net institute in bangalore
aws training in bangalore
Data Science Courses in Bangalore
DevOps Training in Bangalore
PHP Training in bangalore
spoken english classes in bangalore
dot net training in marathahalli

sasi said...

The blog you shared is very good. I expect more information from you like this blog. Thankyou.
Web Designing Course in chennai
Web Designing Course in bangalore
web designing course in coimbatore
web designing training in bangalore
web designing course in madurai
Web Development courses in bangalore
Web development training in bangalore
Salesforce training in bangalore
Web Designing Course in bangalore with placement
web designing training institute in chennai

Big Data Analytics Malaysia said...

I really enjoy simply reading all of your weblogs. Simply wanted to inform you that you have people like me who appreciate your work. Definitely a great post. Hats off to you! The information that you have provided is very helpful.

artificial intelligence in malaysia

yadav said...
Vivek Vichu said...

Awesome blog, very informative content... Thanks for sharing waiting for next update...
Artificial Intelligence Course in Chennai
AI Training in chennai
best artificial intelligence training in chennai
C C++ Training in Chennai
javascript training in chennai
Html5 Training in Chennai
QTP Training in Chennai
Spring Training in Chennai
DOT NET Training in Chennai