C program for prime numbers between 1 to n




Program or code for prime numbers between 1 to n in c language

#include<stdio.h>

int main(){

    int num,i,count,n;
    printf("Enter max range: ");
    scanf("%d",&n);

    for(num = 1;num<=n;num++){

         count = 0;

         for(i=2;i<=num/2;i++){
             if(num%i==0){
                 count++;
                 break;
             }
        }
        
         if(count==0 && num!= 1)
             printf("%d ",num);
    }
  
   return 0;
}

Sample output:
Enter max range: 50
2 3 5 7 11 13


Algorithm:


Definition of prime number:

A natural number greater than one which has not any other divisors except 1 and itself is called prime number. In other word we can say which has only two divisors 1 and number itself. For example: 5

Their divisors are 1 and 5.

Note: 2 is only even prime number.

Logic for prime number in c
We will take a loop and divide number from 2 to number/2. If the number is not divisible by any of the numbers then we will print it as prime number.

Example of prime numbers : 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199 etc.



10 comments:

Anonymous said...

Nice Qusation...But I not minded.......

Anonymous said...

Print all the prime numbers which are below the given number separated by comma

Unknown said...

used very much tq......

K Kumar said...

is this type of algorithm consider as series of prime numbers

Unknown said...

Print all the Armstrong number upto n

Unknown said...

Why is there num/2 ?

Unknown said...

Don't add break; after count++....then it is running properly

Unknown said...

It worked thanks

Tanishq said...

How can I find also their total Sum of Prime numbers between 1 to n?

Mudassar Iqbal said...

#include
int main(){
int n, sum=0;
printf("Enter any number to find it is prime or not \n");
scanf("%d", &n);
printf("Following are the prime numbers between 1 to n \n");
for(int i=1; i<n; i++){
int c=0;
for(int j=2; j<i; j++){
if(i%j==0){
c++;
break;
}

}
if(c==0 && i!=1){
sum=sum+i;
printf("%d \n", i);
}
}
printf("Sum of prime numbers between 1 and n is %d", sum);
}